If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2=64/729
We move all terms to the left:
x^2-(64/729)=0
We add all the numbers together, and all the variables
x^2-(+64/729)=0
We get rid of parentheses
x^2-64/729=0
We multiply all the terms by the denominator
x^2*729-64=0
Wy multiply elements
729x^2-64=0
a = 729; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·729·(-64)
Δ = 186624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{186624}=432$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-432}{2*729}=\frac{-432}{1458} =-8/27 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+432}{2*729}=\frac{432}{1458} =8/27 $
| 2(2x+15)=8x-12 | | (9x-15)-(10x-15=) | | x–13=8 | | 4x-23/4=3x | | -15+j=-4j | | Y-12=12x-12 | | 5+x-6=4*x+2 | | 1-5x=-11-x | | 11/3=y/6 | | -9x=-4(x-5) | | 16=36-v | | -(2x-3)=29 | | 2w^2+w+3=0 | | -m-17=-7m+2-13m | | 2x+4(3x-2)=6 | | 4(a+5)=10+4a | | 2x−13=21 | | -3/4(m-4)=9 | | 3(y-2)=-6+3y | | 10=v+4-3v | | n-4/8=-3 | | 21(2-i)+12i=44 | | 3x+1+5x=7+15x+7x | | X-10+3x=2(2x-4) | | 5-6x-19=-18 | | |2x-3|=29 | | (5-m)=30+8m | | 12/5=-3x | | 3(y-2)=-6=3y | | 6(3r-4)=3/8(40r+8) | | 2x+3x=20, | | 3z+3/8=4z+1/8 |